18x^2=+48x-32

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Solution for 18x^2=+48x-32 equation: 



18x^2=+48x-32

We move all terms to the left:

18x^2-(+48x-32)=0

We add all the numbers together, and all the variables

18x^2-(48x-32)=0

We get rid of parentheses

18x^2-48x+32=0

a = 18; b = -48; c = +32;
Δ = b2-4ac
Δ = -482-4·18·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{48}{36}=1+1/3$

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